9.1.7 Checkerboard V2 Answers -

for (int row = 0; row < 8; row++) for (int col = 0; col < 8; col++) if ((row + col) % 2 == 0) board[row][col] = Color.RED; else board[row][col] = Color.BLACK;

"Right," Maya smiled. "You don't need a complex if-else chain to check the row number separately. You just need to check if (row + column) % 2 == 0 ." 9.1.7 checkerboard v2 answers

Leo paused. "Well... the loop restarts. So j starts at 0 again. Column 0 is black again." for (int row = 0; row &lt; 8;

and use a loop to append eight sub-lists, each containing eight zeros, to establish the structure. 2. Implement alternating logic Use nested for (int row = 0